# ?Which opcode would you use to push the value 5 onto the stack in the most efficient way?

* [ ] 0x05 <0x05>
* [ ] OP\_PUSHDATA1 0x01 0x05
* [x] OP\_5
* [ ] OP\_1 OP\_1 OP\_1 OP\_1 OP\_1 OP\_ADD OP\_ADD OP\_ADD OP\_ADD

Note to learners:

For small integers from -1 to 16, constant value opcodes like OP\_5 are the most efficient approach, using just a single byte. While option D would eventually produce 5 on the stack, it wastes many bytes and execution steps.


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